What is the answer to log_{4}((x+1)/(2x-1))=0 ?

The answer to log_{4}((x+1)/(2x-1))=0 is x=2

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log_{4}((x+1)/(2x-1))=0

lo g_{4} (\frac{x + 1}{2 x - 1}) = 0

x = 2

Solution steps

lo g_{4} (\frac{x + 1}{2 x - 1}) = 0

Apply log rules

\frac{x + 1}{2 x - 1} = 4^{0}

Multiply both sides by

2 x - 1

\frac{x + 1}{2 x - 1} (2 x - 1) = 4^{0} (2 x - 1)

Simplify

x + 1 = 2 x - 1

Solve

x + 1 = 2 x - 1 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{10} (2 x) + 1 = 0

lo g_{y} (36) = 1.842

x, lo g_{10} (3 x + 7) = 2

x, lo g_{2} (x^{2} y) = - 3

lo g_{27} (x) = \frac{- 2}{3}

What is the answer to log_{4}((x+1)/(2x-1))=0 ?
The answer to log_{4}((x+1)/(2x-1))=0 is x=2
Solve for x: log_{4}((x+1)/(2x-1))=0
The solution is x=2