What is the answer to 2*ln(x)-ln(2)=ln(2x-1) ?

The answer to 2*ln(x)-ln(2)=ln(2x-1) is x=2+sqrt(2),x=2-sqrt(2)

Solve for x: 2*ln(x)-ln(2)=ln(2x-1)

The solution is x=2+sqrt(2),x=2-sqrt(2)

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2 \cdot ln (x) - ln (2) = ln (2 x - 1)

x = 2 + 2, x = 2 - 2

Decimal Notation

x = 3.41421 \dots, x = 0.58578 \dots

Solution steps

2 ln (x) - ln (2) = ln (2 x - 1)

Apply log rules

x^{2} = (2 x - 1) \cdot 2

Solve

x^{2} = (2 x - 1) \cdot 2 : x = 2 + 2, x = 2 - 2

x = 2 + 2, x = 2 - 2

Verify Solutions:

x = 2 + 2

True

, x = 2 - 2

True

The solutions are

x = 2 + 2, x = 2 - 2

lo g_{3} (4 x - 5) = lo g_{3} (x + 3)

20 lo g_{10} (x) = 29.5

lo g_{3} (x + 58) = lo g_{3} (x + 2) + 2

lo g_{6} (x + 5) = 36

ln (2 x + 1) = 0

What is the answer to 2*ln(x)-ln(2)=ln(2x-1) ?
The answer to 2*ln(x)-ln(2)=ln(2x-1) is x=2+sqrt(2),x=2-sqrt(2)
Solve for x: 2*ln(x)-ln(2)=ln(2x-1)
The solution is x=2+sqrt(2),x=2-sqrt(2)