What is the answer to log_{5}(8x)-log_{5}(2)=0 ?

The answer to log_{5}(8x)-log_{5}(2)=0 is x= 1/4

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log_{5}(8x)-log_{5}(2)=0

lo g_{5} (8 x) - lo g_{5} (2) = 0

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

lo g_{5} (8 x) - lo g_{5} (2) = 0

Move

lo g_{5} (2)

to the right side

lo g_{5} (8 x) = lo g_{5} (2)

Apply log rules

8 x = 2

Solve

8 x = 2 : x = \frac{1}{4}

x = \frac{1}{4}

Verify Solutions:

x = \frac{1}{4}

True

The solution is

x = \frac{1}{4}

lo g_{3} (9 x \cdot 8) = 5

ln (x) = 3.43

lo g_{2} (2^{x + 1} - 8) = x

ln (x) = 3.53

ln (x) = 3.57

What is the answer to log_{5}(8x)-log_{5}(2)=0 ?
The answer to log_{5}(8x)-log_{5}(2)=0 is x= 1/4
Solve for x: log_{5}(8x)-log_{5}(2)=0
The solution is x= 1/4