What is the answer to log_{4}(x)=2+log_{16}(x) ?

The answer to log_{4}(x)=2+log_{16}(x) is x=256

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log_{4}(x)=2+log_{16}(x)

lo g_{4} (x) = 2 + lo g_{16} (x)

x = 256

Solution steps

lo g_{4} (x) = 2 + lo g_{16} (x)

Apply log rules

x = 256

Verify Solutions:

x = 256

True

The solution is

x = 256

lo g_{5} (x) = \frac{1}{5}

lo g_{4} (x + 10) + lo g_{4} (x - 5) = 2

lo g_{2} (x^{2} - 16) = 0

lo g_{2} (x + 2) - lo g_{2} (x - 1) = 2

2 ln (x) - ln (x + 5) + ln (3) = ln (x)

What is the answer to log_{4}(x)=2+log_{16}(x) ?
The answer to log_{4}(x)=2+log_{16}(x) is x=256
Solve for x: log_{4}(x)=2+log_{16}(x)
The solution is x=256