What is the answer to log_{3}(5)+log_{3}(X-6)=2 ?

The answer to log_{3}(5)+log_{3}(X-6)=2 is X= 39/5

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log_{3}(5)+log_{3}(X-6)=2

lo g_{3} (5) + lo g_{3} (X - 6) = 2

X = \frac{39}{5}

Decimal Notation

X = 7.8

Solution steps

lo g_{3} (5) + lo g_{3} (X - 6) = 2

Move

lo g_{3} (5)

to the right side

lo g_{3} (X - 6) = 2 - lo g_{3} (5)

Apply log rules

X - 6 = \frac{9}{5}

Solve

X - 6 = \frac{9}{5} : X = \frac{39}{5}

X = \frac{39}{5}

Verify Solutions:

X = \frac{39}{5}

True

The solution is

X = \frac{39}{5}

lo g_{10} (x) = 15.2

3^{2} = [lo g_{3} (x + 5)]^{3}

ln (x e^{x}) = ln (5 e^{x} - 5)

ln (x) = 3 - 2 x

lo g_{a} (1 0^{1.8}) = 2.5752

What is the answer to log_{3}(5)+log_{3}(X-6)=2 ?
The answer to log_{3}(5)+log_{3}(X-6)=2 is X= 39/5
Solve for X: log_{3}(5)+log_{3}(X-6)=2
The solution is X= 39/5