What is the answer to 3^2=[log_{3}(x+5)]^3 ?

The answer to 3^2=[log_{3}(x+5)]^3 is x=3^{\sqrt[3]{9}}-5

Solve for x: 3^2=[log_{3}(x+5)]^3

The solution is x=3^{\sqrt[3]{9}}-5

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3^{2} = [lo g_{3} (x + 5)]^{3}

Decimal Notation

x = 4.82770 \dots

Solution steps

3^{2} = [lo g_{3} (x + 5)]^{3}

Rewrite the equation with

lo g_{3} (x + 5) = u

3^{2} = [u]^{3}

Solve

Substitute back

u = lo g_{3} (x + 5),

solve for

x

Solve

Verify Solutions:

True

The solution is

ln (x e^{x}) = ln (5 e^{x} - 5)

ln (x) = 3 - 2 x

lo g_{a} (1 0^{1.8}) = 2.5752

85.6 = 10 \cdot lo g_{10} (W)

lo g_{10} (p) = - 2.6

What is the answer to 3^2=[log_{3}(x+5)]^3 ?
The answer to 3^2=[log_{3}(x+5)]^3 is x=3^{\sqrt[3]{9}}-5
Solve for x: 3^2=[log_{3}(x+5)]^3
The solution is x=3^{\sqrt[3]{9}}-5