What is the answer to log_{10}(p)=-2.6 ?

The answer to log_{10}(p)=-2.6 is p= 1/(10^{2.6)}

Solve for p: log_{10}(p)=-2.6

The solution is p= 1/(10^{2.6)}

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lo g_{10} (p) = - 2.6

p = \frac{1}{1 0 ^{2.6}}

Decimal Notation

p = 0.00251 \dots

Solution steps

lo g_{10} (p) = - 2.6

Apply log rules

p = \frac{1}{1 0 ^{2.6}}

ln (4 x) - 6 ln (x) = ln (2)

ln (x + 2) + ln (x - 1) = 1

lo g_{5} (3 x - 1) = 2

- 11 = ln (0^{2} + x)

- ln (126) = 4 ln (p) + 5 ln (1 - p)

What is the answer to log_{10}(p)=-2.6 ?
The answer to log_{10}(p)=-2.6 is p= 1/(10^{2.6)}
Solve for p: log_{10}(p)=-2.6
The solution is p= 1/(10^{2.6)}