What is the answer to ln(1-c)=0.46 ?

The answer to ln(1-c)=0.46 is c=-e^{0.46}+1

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ln(1-c)=0.46

ln (1 - c) = 0.46

c = - e^{0.46} + 1

Decimal Notation

c = - 0.58407 \dots

Solution steps

ln (1 - c) = 0.46

Apply log rules

1 - c = e^{0.46}

Solve

1 - c = e^{0.46} : c = - e^{0.46} + 1

c = - e^{0.46} + 1

y, x = lo g_{10} (y + 2)

lo g_{10} (x + 3) = 4 lo g_{10} (x)

0 = 1 + lo g_{5} (x - 4)

2 ln (X) - 3 = ln (A^{2} - e^{3})

20 \cdot lo g_{10} (x \cdot 2) = 20

What is the answer to ln(1-c)=0.46 ?
The answer to ln(1-c)=0.46 is c=-e^{0.46}+1
Solve for c: ln(1-c)=0.46
The solution is c=-e^{0.46}+1