What is the answer to log_{4}(8)+log_{4}(x)=5 ?

The answer to log_{4}(8)+log_{4}(x)=5 is x=128

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log_{4}(8)+log_{4}(x)=5

lo g_{4} (8) + lo g_{4} (x) = 5

x = 128

Solution steps

lo g_{4} (8) + lo g_{4} (x) = 5

Move

lo g_{4} (8)

to the right side

lo g_{4} (x) = 5 - lo g_{4} (8)

Apply log rules

x = 4^{5 - \frac{3}{2}}

Solve

x = 4^{5 - \frac{3}{2}} : x = 128

x = 128

Verify Solutions:

x = 128

True

The solution is

x = 128

2 lo g_{4} (x) - lo g_{4} (3 x - 5) = 1

2.88 = - lo g_{10} (x)

lo g_{3} (2 x + 1) - lo g_{3} (x + 7) = 1

ln (x) = - \frac{1}{40}

ln (x + 2.8) = 1.6

What is the answer to log_{4}(8)+log_{4}(x)=5 ?
The answer to log_{4}(8)+log_{4}(x)=5 is x=128
Solve for x: log_{4}(8)+log_{4}(x)=5
The solution is x=128