What is the answer to log_{3}(f+2)-log_{3}(f+5)=2 ?

The answer to log_{3}(f+2)-log_{3}(f+5)=2 is No Solution for f\in\mathbb{R}

Solve for f: log_{3}(f+2)-log_{3}(f+5)=2

The solution is No Solution for f\in\mathbb{R}

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lo g_{3} (f + 2) - lo g_{3} (f + 5) = 2

No Solution for f \in R

Solution steps

lo g_{3} (f + 2) - lo g_{3} (f + 5) = 2

Add

lo g_{3} (f + 5)

to both sides

lo g_{3} (f + 2) - lo g_{3} (f + 5) + lo g_{3} (f + 5) = 2 + lo g_{3} (f + 5)

Simplify

lo g_{3} (f + 2) = 2 + lo g_{3} (f + 5)

Apply log rules

f + 2 = 9 (f + 5)

Solve

f + 2 = 9 (f + 5) : f = - \frac{43}{8}

f = - \frac{43}{8}

Verify Solutions:

f = - \frac{43}{8}

False

The solution is

No Solution for f \in R

ln (x + 5) + 3 = 2

x, ln (x y) + 4 x = 35

x, ln (x y) + 4 x = 45

20 lo g_{10} (g) = 62.33

lo g_{9} (x) = a \cdot lo g_{3} (x)

What is the answer to log_{3}(f+2)-log_{3}(f+5)=2 ?
The answer to log_{3}(f+2)-log_{3}(f+5)=2 is No Solution for f\in\mathbb{R}
Solve for f: log_{3}(f+2)-log_{3}(f+5)=2
The solution is No Solution for f\in\mathbb{R}