What are the solutions to the equation (2a-6)(3a+15)=0 ?

The solutions to the equation (2a-6)(3a+15)=0 are a=3,a=-5

Find the zeros of (2a-6)(3a+15)=0

The zeros of (2a-6)(3a+15)=0 are a=3,a=-5

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(2 a - 6) (3 a + 15) = 0

a = 3, a = - 5

Solution steps

(2 a - 6) (3 a + 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 a - 6 = 0 or 3 a + 15 = 0

Solve

2 a - 6 = 0 : a = 3

Solve

3 a + 15 = 0 : a = - 5

The solutions to the quadratic equation are:

a = 3, a = - 5

x^{2} - 10 x + 15 = 0

4 x + 7 (3 x - 3) \leq 9 - 5 x

3 x - 2 + \frac{1}{2} = x - 7 + (\frac{1}{4}) x + 2

2 - 5 x \leq 1

12 5^{\frac{3}{2}}

What are the solutions to the equation (2a-6)(3a+15)=0 ?
The solutions to the equation (2a-6)(3a+15)=0 are a=3,a=-5
Find the zeros of (2a-6)(3a+15)=0
The zeros of (2a-6)(3a+15)=0 are a=3,a=-5