What is the answer to ln(2)=ln(1(0-1)+c) ?

The answer to ln(2)=ln(1(0-1)+c) is c=3

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ln(2)=ln(1(0-1)+c)

ln (2) = ln (1 (0 - 1) + c)

c = 3

Solution steps

ln (2) = ln (1 \cdot (0 - 1) + c)

Apply log rules

2 = - 1 + c

Solve

2 = - 1 + c : c = 3

c = 3

Verify Solutions:

c = 3

True

The solution is

c = 3

ln (\frac{2}{5 x}) = ln (5)

4 lo g_{3} (4 x - 12) = 8

x, - 4 ln (2 x) = - 2.773

lo g_{10} (5) (2 x + 3) = lo g_{8} (x)

lo g_{10} (x) + lo g_{100} (x) = 3

What is the answer to ln(2)=ln(1(0-1)+c) ?
The answer to ln(2)=ln(1(0-1)+c) is c=3
Solve for c: ln(2)=ln(1(0-1)+c)
The solution is c=3