What are the solutions to the equation x^2-6x=-6 ?

The solutions to the equation x^2-6x=-6 are x=3+sqrt(3),x=3-sqrt(3)

Find the zeros of x^2-6x=-6

The zeros of x^2-6x=-6 are x=3+sqrt(3),x=3-sqrt(3)

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x^{2} - 6 x = - 6

x = 3 + 3, x = 3 - 3

Solution steps

x^{2} - 6 x = - 6

Move

6

to the left side

x^{2} - 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 6 = 23

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 3}{2 \cdot 1} : 3 + 3

x = \frac{- ( - 6 ) - 2 3}{2 \cdot 1} : 3 - 3

The solutions to the quadratic equation are:

x = 3 + 3, x = 3 - 3

x + ∣ x ∣ = 0

\frac{X}{- 8} \geq - 5

- 4 x + 1 \leq - 7

7 + 3 x = 2 x + 2

2 x \cdot 10 (\frac{9 - x}{5}) = 18

What are the solutions to the equation x^2-6x=-6 ?
The solutions to the equation x^2-6x=-6 are x=3+sqrt(3),x=3-sqrt(3)
Find the zeros of x^2-6x=-6
The zeros of x^2-6x=-6 are x=3+sqrt(3),x=3-sqrt(3)