What is the answer to ln(3)-ln(x^2+2)=1 ?

The answer to ln(3)-ln(x^2+2)=1 is No Solution for x\in\mathbb{R}

Solve for x: ln(3)-ln(x^2+2)=1

The solution is No Solution for x\in\mathbb{R}

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ln (3) - ln (x^{2} + 2) = 1

No Solution for x \in R

Solution steps

ln (3) - ln (x^{2} + 2) = 1

Move

ln (3)

to the right side

- ln (x^{2} + 2) = 1 - ln (3)

Divide both sides by

- 1

ln (x^{2} + 2) = - 1 + ln (3)

Apply log rules

x^{2} + 2 = \frac{3}{e}

Solve

x^{2} + 2 = \frac{3}{e} :

No Solution for

x \in R

No Solution for x \in R

2 lo g_{4} (3 x - 1) + 5 = 7

lo g_{7} (5 y + 4) = 2

D = 12 - ln (p)

lo g_{3} (2 x) = 5

4.86 = - lo g_{10} (x)

What is the answer to ln(3)-ln(x^2+2)=1 ?
The answer to ln(3)-ln(x^2+2)=1 is No Solution for x\in\mathbb{R}
Solve for x: ln(3)-ln(x^2+2)=1
The solution is No Solution for x\in\mathbb{R}