What is the answer to (t)=3log_{2}(-3+t) ?

The answer to (t)=3log_{2}(-3+t) is No Solution for t\in\mathbb{R}

Solve for t: (t)=3log_{2}(-3+t)

The solution is No Solution for t\in\mathbb{R}

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(t) = 3 lo g_{2} (- 3 + t)

No Solution for t \in R

Solution steps

(t) = 3 lo g_{2} (- 3 + t)

Switch sides

3 lo g_{2} (- 3 + t) = t

Divide both sides by

3

lo g_{2} (- 3 + t) = \frac{t}{3}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (- 3 + t)} = 2^{\frac{t}{3}}

Simplify

2^{l o g_{2} (- 3 + t)} : - 3 + t

- 3 + t = 2^{\frac{t}{3}}

Solve

- 3 + t = 2^{\frac{t}{3}} :

No Solution for

t \in R

No Solution for t \in R

lo g_{a} (x) = - \frac{1}{ln ( a )}

20 lo g_{10} (\frac{1}{k}) = 17.1

y, ln (y) = - 2 t

lo g_{10} (x) = - 1.187087

lo g_{27} (x) = lo g_{3} (x) + 2

What is the answer to (t)=3log_{2}(-3+t) ?
The answer to (t)=3log_{2}(-3+t) is No Solution for t\in\mathbb{R}
Solve for t: (t)=3log_{2}(-3+t)
The solution is No Solution for t\in\mathbb{R}