What is the answer to 2.68=-log_{10}(x) ?

The answer to 2.68=-log_{10}(x) is x= 1/(10^{2.68)}

Solve for x: 2.68=-log_{10}(x)

The solution is x= 1/(10^{2.68)}

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2.68 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{2.68}}

Decimal

x = 0.00208 \dots

Solution steps

2.68 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

2.68 + lo g_{10} (x) = 0

Move

2.68

to the right side

lo g_{10} (x) = - 2.68

Apply log rules

x = \frac{1}{1 0 ^{2.68}}

Verify Solutions:

x = \frac{1}{1 0 ^{2.68}}

True

The solution is

x = \frac{1}{1 0 ^{2.68}}

1 + 3.3 lo g_{10} (x) = 6

ln (x - 3) - ln (x) + 2 ln (2) + 10 = 0

x, ln (x y) + 4 x = 15

10.26 = - lo g_{10} (x)

x, ln (y) = ln (x^{2}) + C

What is the answer to 2.68=-log_{10}(x) ?
The answer to 2.68=-log_{10}(x) is x= 1/(10^{2.68)}
Solve for x: 2.68=-log_{10}(x)
The solution is x= 1/(10^{2.68)}