What is the answer to log_{10}(x^2+2x-8)=0 ?

The answer to log_{10}(x^2+2x-8)=0 is x=-1+sqrt(10),x=-1-sqrt(10)

Solve for x: log_{10}(x^2+2x-8)=0

The solution is x=-1+sqrt(10),x=-1-sqrt(10)

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lo g_{10} (x^{2} + 2 x - 8) = 0

x = - 1 + 10, x = - 1 - 10

Decimal Notation

x = 2.16227 \dots, x = - 4.16227 \dots

Solution steps

lo g_{10} (x^{2} + 2 x - 8) = 0

Apply log rules

x^{2} + 2 x - 8 = 1

Solve

x^{2} + 2 x - 8 = 1 : x = - 1 + 10, x = - 1 - 10

x = - 1 + 10, x = - 1 - 10

x^{2} = 2 x^{2} ln (x)

- ln (2 + x) = 2

ln (x^{2} + 2 x) = ln (x)

y, ln (y) = 0

lo g_{2} (x) + lo g_{2} (2) = 10

What is the answer to log_{10}(x^2+2x-8)=0 ?
The answer to log_{10}(x^2+2x-8)=0 is x=-1+sqrt(10),x=-1-sqrt(10)
Solve for x: log_{10}(x^2+2x-8)=0
The solution is x=-1+sqrt(10),x=-1-sqrt(10)