What is the answer to ln(x^2+2x)=ln(x) ?

The answer to ln(x^2+2x)=ln(x) is No Solution for x\in\mathbb{R}

Solve for x: ln(x^2+2x)=ln(x)

The solution is No Solution for x\in\mathbb{R}

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ln (x^{2} + 2 x) = ln (x)

No Solution for x \in R

Solution steps

ln (x^{2} + 2 x) = ln (x)

Apply log rules

x^{2} + 2 x = x

Solve

x^{2} + 2 x = x : x = 0, x = - 1

x = 0, x = - 1

Verify Solutions:

x = 0

False

, x = - 1

False

The solution is

No Solution for x \in R

y, ln (y) = 0

lo g_{2} (x) + lo g_{2} (2) = 10

ln (x) = 11.93

lo g_{6} (x - 2) + lo g_{6} (x - 1) = 1

y, - 1 (ln (y)) = ln (x) + c

What is the answer to ln(x^2+2x)=ln(x) ?
The answer to ln(x^2+2x)=ln(x) is No Solution for x\in\mathbb{R}
Solve for x: ln(x^2+2x)=ln(x)
The solution is No Solution for x\in\mathbb{R}