What is the answer to solvefor y,-1(ln(y))=ln(x)+c ?

The answer to solvefor y,-1(ln(y))=ln(x)+c is y=(e^{-c})/x

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solvefor y,-1(ln(y))=ln(x)+c

solve for

y, - 1 (ln (y)) = ln (x) + c

y = \frac{e ^{- c}}{x}

Solution steps

- 1 \cdot (ln (y)) = ln (x) + c

Divide both sides by

- 1

ln (y) = - ln (x) - c

Apply log rules

y = \frac{e ^{- c}}{x}

y, - ln (4 - y) = x

lo g_{10} (2 x) - 20 = 2

2.34 = ln (x)

ln (z) - ln (3) = \frac{3}{2}

lo g_{10} (x) 2 + lo g_{10} (2 x) = 0

What is the answer to solvefor y,-1(ln(y))=ln(x)+c ?
The answer to solvefor y,-1(ln(y))=ln(x)+c is y=(e^{-c})/x