What is the answer to log_{10}(2x)-20=2 ?

The answer to log_{10}(2x)-20=2 is x=5^{22}*2097152

Solve for x: log_{10}(2x)-20=2

The solution is x=5^{22}*2097152

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lo g_{10} (2 x) - 20 = 2

x = 5^{22} \cdot 2097152

Decimal Notation

x = 5.0 E 21

Solution steps

lo g_{10} (2 x) - 20 = 2

Move

20

to the right side

lo g_{10} (2 x) = 22

Apply log rules

2 x = 1 0^{22}

Solve

2 x = 1 0^{22} : x = 5^{22} \cdot 2097152

x = 5^{22} \cdot 2097152

Verify Solutions:

x = 5^{22} \cdot 2097152

True

The solution is

x = 5^{22} \cdot 2097152

2.34 = ln (x)

ln (z) - ln (3) = \frac{3}{2}

lo g_{10} (x) 2 + lo g_{10} (2 x) = 0

1 = lo g_{10} (\frac{0.05}{x})

2 lo g_{2} (x^{5}) - lo g_{2} (x) = 6

What is the answer to log_{10}(2x)-20=2 ?
The answer to log_{10}(2x)-20=2 is x=5^{22}*2097152
Solve for x: log_{10}(2x)-20=2
The solution is x=5^{22}*2097152