What is the answer to solvefor b,log_{b}(9)=2 ?

The answer to solvefor b,log_{b}(9)=2 is b=3

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solvefor b,log_{b}(9)=2

solve for

b, lo g_{b} (9) = 2

b = 3

Solution steps

lo g_{b} (9) = 2

Apply log rules

\frac{1}{lo g _{9} ( b )} = 2

Multiply both sides by

lo g_{9} (b)

\frac{1}{lo g _{9} ( b )} lo g_{9} (b) = 2 lo g_{9} (b)

Simplify

1 = 2 lo g_{9} (b)

Switch sides

2 lo g_{9} (b) = 1

Divide both sides by

2

lo g_{9} (b) = \frac{1}{2}

Apply log rules

b = 3

Verify Solutions:

b = 3

True

The solution is

b = 3

0.24 = lo g_{10} (\frac{x}{1 - x})

lo g_{10} (\frac{1}{x}) = - 4

lo g_{5} (x + 4) + lo g_{5} (x - 4) = 2

ln (7 x + 32) + ln (4) = 2 ln (x)

1 = lo g_{10} (2 x^{2} + 3 x - 22)

What is the answer to solvefor b,log_{b}(9)=2 ?
The answer to solvefor b,log_{b}(9)=2 is b=3