What is the answer to 2=log_{x}(3^2) ?

The answer to 2=log_{x}(3^2) is x=3

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2=log_{x}(3^2)

2 = lo g_{x} (3^{2})

x = 3

Solution steps

2 = lo g_{x} (3^{2})

Apply log rules

2 = \frac{ln ( 3 ^{2} )}{ln ( x )}

Multiply both sides by

ln (x)

2 ln (x) = \frac{ln ( 3 ^{2} )}{ln ( x )} ln (x)

Apply log rules

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

lo g_{x} (x) = 2

ln (t) - 1.3527300000000 \dots = 0.0897700000000 \dots

4.23 = 3.86 + lo g_{10} (x)

lo g_{3} (x) = lo g_{10} (9) (2 x + 7)

lo g_{10} (x) = 0.87064