What is the answer to log_{2}(2x+2)=0 ?

The answer to log_{2}(2x+2)=0 is x=-1/2

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log_{2}(2x+2)=0

lo g_{2} (2 x + 2) = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

lo g_{2} (2 x + 2) = 0

Apply log rules

2 x + 2 = 1

Solve

2 x + 2 = 1 : x = - \frac{1}{2}

x = - \frac{1}{2}

lo g_{2} (2 x + 2) = 1

lo g_{4} (x + 6) + lo g_{4} (x) = 2

(x + 12) = ln (x) + ln (12)

lo g_{3} (3) + lo g_{3} (x) = 10

ln (x + 3) - 5 = - 2