What is the answer to log_{4}(x+6)+log_{4}(x)=2 ?

The answer to log_{4}(x+6)+log_{4}(x)=2 is x=2

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log_{4}(x+6)+log_{4}(x)=2

lo g_{4} (x + 6) + lo g_{4} (x) = 2

x = 2

Solution steps

lo g_{4} (x + 6) + lo g_{4} (x) = 2

Apply log rules

(x + 6) x = 16

Solve

(x + 6) x = 16 : x = 2, x = - 8

x = 2, x = - 8

Verify Solutions:

x = 2

True

, x = - 8

False

The solution is

x = 2

(x + 12) = ln (x) + ln (12)

lo g_{3} (3) + lo g_{3} (x) = 10

ln (x + 3) - 5 = - 2

lo g_{10} (x) = 18.82

ln (3 x - 1) = ln (2) + ln (4 x - 6)

What is the answer to log_{4}(x+6)+log_{4}(x)=2 ?
The answer to log_{4}(x+6)+log_{4}(x)=2 is x=2
Solve for x: log_{4}(x+6)+log_{4}(x)=2
The solution is x=2