What is the answer to log_{5}(x-11)+log_{5}(x-6)=2 ?

The answer to log_{5}(x-11)+log_{5}(x-6)=2 is x=(17+5sqrt(5))/2

Solve for x: log_{5}(x-11)+log_{5}(x-6)=2

The solution is x=(17+5sqrt(5))/2

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lo g_{5} (x - 11) + lo g_{5} (x - 6) = 2

x = \frac{17 + 5 5}{2}

Decimal Notation

x = 14.09016 \dots

Solution steps

lo g_{5} (x - 11) + lo g_{5} (x - 6) = 2

Apply log rules

(x - 11) (x - 6) = 25

Solve

(x - 11) (x - 6) = 25 : x = \frac{17 + 5 5}{2}, x = \frac{17 - 5 5}{2}

x = \frac{17 + 5 5}{2}, x = \frac{17 - 5 5}{2}

Verify Solutions:

x = \frac{17 + 5 5}{2}

True

, x = \frac{17 - 5 5}{2}

False

The solution is

x = \frac{17 + 5 5}{2}

6 = - lo g_{x} (x)

lo g_{10} (m) = 8.92

lo g_{10} (x) = - 0.25

lo g_{10} (x) = - 0.12

lo g_{10} (x) - lo g_{10} (2 - x) = 0

What is the answer to log_{5}(x-11)+log_{5}(x-6)=2 ?
The answer to log_{5}(x-11)+log_{5}(x-6)=2 is x=(17+5sqrt(5))/2
Solve for x: log_{5}(x-11)+log_{5}(x-6)=2
The solution is x=(17+5sqrt(5))/2