What is the answer to log_{10}(1-d)=-0.19 ?

The answer to log_{10}(1-d)=-0.19 is d=(-1+10^{0.19})/(10^{0.19)}

Solve for d: log_{10}(1-d)=-0.19

The solution is d=(-1+10^{0.19})/(10^{0.19)}

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lo g_{10} (1 - d) = - 0.19

d = \frac{- 1 + 1 0 ^{0.19}}{1 0 ^{0.19}}

Decimal Notation

d = 0.35434 \dots

Solution steps

lo g_{10} (1 - d) = - 0.19

Apply log rules

1 - d = \frac{1}{1 0 ^{0.19}}

Solve

1 - d = \frac{1}{1 0 ^{0.19}} : d = \frac{- 1 + 1 0 ^{0.19}}{1 0 ^{0.19}}

d = \frac{- 1 + 1 0 ^{0.19}}{1 0 ^{0.19}}

3 lo g_{4} (4 x) = 6

y, 2 ln (y + 2) = 2 x^{2} + C

x 6 - 5 ln (x) = 2

ln (3 x) = 3 ln (x)

lo g_{64} (x) = 4

What is the answer to log_{10}(1-d)=-0.19 ?
The answer to log_{10}(1-d)=-0.19 is d=(-1+10^{0.19})/(10^{0.19)}
Solve for d: log_{10}(1-d)=-0.19
The solution is d=(-1+10^{0.19})/(10^{0.19)}