What is the answer to solvefor y,2ln(y+2)=2x^2+C ?

The answer to solvefor y,2ln(y+2)=2x^2+C is y=e^{(2x^2+C)/2}-2

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solvefor y,2ln(y+2)=2x^2+C

solve for

y, 2 ln (y + 2) = 2 x^{2} + C

y = e^{\frac{2 x ^{2} + C}{2}} - 2

Solution steps

2 ln (y + 2) = 2 x^{2} + C

Divide both sides by

2

ln (y + 2) = \frac{2 x ^{2} + C}{2}

Apply log rules

y + 2 = e^{\frac{2 x ^{2} + C}{2}}

Solve

y + 2 = e^{\frac{2 x ^{2} + C}{2}} : y = e^{\frac{2 x ^{2} + C}{2}} - 2

y = e^{\frac{2 x ^{2} + C}{2}} - 2

x 6 - 5 ln (x) = 2

ln (3 x) = 3 ln (x)

lo g_{64} (x) = 4

2 lo g_{2} (y) = lo g_{4} (3)

3 lo g_{2} (x + 1) - 2 = 13

What is the answer to solvefor y,2ln(y+2)=2x^2+C ?
The answer to solvefor y,2ln(y+2)=2x^2+C is y=e^{(2x^2+C)/2}-2