What is the answer to log_{3}(5x+2)+log_{3}(6)=5 ?

The answer to log_{3}(5x+2)+log_{3}(6)=5 is x= 77/10

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log_{3}(5x+2)+log_{3}(6)=5

lo g_{3} (5 x + 2) + lo g_{3} (6) = 5

x = \frac{77}{10}

Decimal Notation

x = 7.7

Solution steps

lo g_{3} (5 x + 2) + lo g_{3} (6) = 5

Move

lo g_{3} (6)

to the right side

lo g_{3} (5 x + 2) = 5 - lo g_{3} (6)

Apply log rules

5 x + 2 = \frac{81}{2}

Solve

5 x + 2 = \frac{81}{2} : x = \frac{77}{10}

x = \frac{77}{10}

Verify Solutions:

x = \frac{77}{10}

True

The solution is

x = \frac{77}{10}

lo g_{x} (10) = lo g_{10} (x)

lo g_{4} (- 8 - 4 x) = 1

ln (5 x) = 3

1 + 2 lo g_{3} (x) = lo g_{3} (28 x - 9)

ln (10 - 3 x) = ln (- 4 x)

What is the answer to log_{3}(5x+2)+log_{3}(6)=5 ?
The answer to log_{3}(5x+2)+log_{3}(6)=5 is x= 77/10
Solve for x: log_{3}(5x+2)+log_{3}(6)=5
The solution is x= 77/10