What is the answer to 4=log_{10}(g)6561 ?

The answer to 4=log_{10}(g)6561 is g=10^{4/6561}

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4=log_{10}(g)6561

4 = lo g_{10} (g) 6561

g = 1 0^{\frac{4}{6561}}

Decimal Notation

g = 1.00140 \dots

Solution steps

4 = lo g_{10} (g) \cdot 6561

Switch sides

lo g_{10} (g) \cdot 6561 = 4

Divide both sides by

6561

lo g_{10} (g) = \frac{4}{6561}

Apply log rules

g = 1 0^{\frac{4}{6561}}

Verify Solutions:

g = 1 0^{\frac{4}{6561}}

True

The solution is

g = 1 0^{\frac{4}{6561}}

lo g_{10} (v) - lo g_{10} (4) = 1

lo g_{10} (x^{2}) = 16

1.1 = ln (x)

2 lo g_{10} (x) - 6 = 0

lo g_{2} (x) + lo g_{x} (2) = 2.5

What is the answer to 4=log_{10}(g)6561 ?
The answer to 4=log_{10}(g)6561 is g=10^{4/6561}
Solve for g: 4=log_{10}(g)6561
The solution is g=10^{4/6561}