What is the answer to log_{10}(v)-log_{10}(4)=1 ?

The answer to log_{10}(v)-log_{10}(4)=1 is v=40

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log_{10}(v)-log_{10}(4)=1

lo g_{10} (v) - lo g_{10} (4) = 1

v = 40

Solution steps

lo g_{10} (v) - lo g_{10} (4) = 1

Move

lo g_{10} (4)

to the right side

lo g_{10} (v) = 1 + lo g_{10} (4)

Apply log rules

v = 40

Verify Solutions:

v = 40

True

The solution is

v = 40

lo g_{10} (x^{2}) = 16

1.1 = ln (x)

2 lo g_{10} (x) - 6 = 0

lo g_{2} (x) + lo g_{x} (2) = 2.5

lo g_{5} (2 x + 23) = lo g_{5} (x - 5)

What is the answer to log_{10}(v)-log_{10}(4)=1 ?
The answer to log_{10}(v)-log_{10}(4)=1 is v=40
Solve for v: log_{10}(v)-log_{10}(4)=1
The solution is v=40