What is the answer to solvefor y=4*ln(x+c),x ?

The answer to solvefor y=4*ln(x+c),x is x=e^{y/4}-c

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solvefor y=4*ln(x+c),x

solve for

y = 4 \cdot ln (x + c), x

x = e^{\frac{y}{4}} - c

Solution steps

y = 4 ln (x + c)

Switch sides

4 ln (x + c) = y

Divide both sides by

4

ln (x + c) = \frac{y}{4}

Apply log rules

x + c = e^{\frac{y}{4}}

Solve

x + c = e^{\frac{y}{4}} : x = e^{\frac{y}{4}} - c

x = e^{\frac{y}{4}} - c

2 = - lo g_{10} (t)

7.3 = 20 lo g_{10} (\frac{4.7}{x})

- 30 = 10 \cdot lo g_{10} (w)

ln (x) - 3 + 2 x = 0

x, z = ln (x y)

What is the answer to solvefor y=4*ln(x+c),x ?
The answer to solvefor y=4*ln(x+c),x is x=e^{y/4}-c