What are the solutions to the equation 0=x^2+8x-33 ?

The solutions to the equation 0=x^2+8x-33 are x=3,x=-11

Find the zeros of 0=x^2+8x-33

The zeros of 0=x^2+8x-33 are x=3,x=-11

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0 = x^{2} + 8 x - 33

x = 3, x = - 11

Solution steps

0 = x^{2} + 8 x - 33

Switch sides

x^{2} + 8 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 33 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 33) = 14

x_{1, 2} = \frac{- 8 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 14}{2 \cdot 1}, x_{2} = \frac{- 8 - 14}{2 \cdot 1}

x = \frac{- 8 + 14}{2 \cdot 1} : 3

x = \frac{- 8 - 14}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 3, x = - 11

- ∣ m + 3 ∣ = - 13

b^{2} + 5 = 8 b - 10

(2)^{\frac{1}{3}}

- \frac{1}{2} (5 x - 8) \geq - 6

\frac{2}{\frac{3}{\frac{1}{3}}}

What are the solutions to the equation 0=x^2+8x-33 ?
The solutions to the equation 0=x^2+8x-33 are x=3,x=-11
Find the zeros of 0=x^2+8x-33
The zeros of 0=x^2+8x-33 are x=3,x=-11