What is the answer to 2/3 log_{2}(2-3x)+8=10 ?

The answer to 2/3 log_{2}(2-3x)+8=10 is x=-2

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2/3 log_{2}(2-3x)+8=10

\frac{2}{3} lo g_{2} (2 - 3 x) + 8 = 10

x = - 2

Solution steps

\frac{2}{3} lo g_{2} (2 - 3 x) + 8 = 10

Move

8

to the right side

\frac{2}{3} lo g_{2} (2 - 3 x) = 2

Multiply both sides by

3

2 lo g_{2} (2 - 3 x) = 6

Divide both sides by

2

lo g_{2} (2 - 3 x) = 3

Apply log rules

2 - 3 x = 8

Solve

2 - 3 x = 8 : x = - 2

x = - 2

Verify Solutions:

x = - 2

True

The solution is

x = - 2

2 lo g_{2} (x) = 2 lo g_{2} (3)

lo g_{10} (y) 32 = 5

lo g_{4} (2) - lo g_{4} (2 - 5 x) = 4

5 lo g_{3} (x) = - 3

y, x = 2 ln (y - 1)

What is the answer to 2/3 log_{2}(2-3x)+8=10 ?
The answer to 2/3 log_{2}(2-3x)+8=10 is x=-2
Solve for x: 2/3 log_{2}(2-3x)+8=10
The solution is x=-2