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Popular >

solvefor y,x=2ln(y-1)

Solution

solve for

y, x = 2 ln (y - 1)

Solution

y = e^{\frac{x}{2}} + 1

Solution steps

x = 2 ln (y - 1)

Switch sides

2 ln (y - 1) = x

Divide both sides by

2

ln (y - 1) = \frac{x}{2}

Apply log rules

y - 1 = e^{\frac{x}{2}}

Solve

y - 1 = e^{\frac{x}{2}} : y = e^{\frac{x}{2}} + 1

y = e^{\frac{x}{2}} + 1

Verify Solutions:

y = e^{\frac{x}{2}} + 1

True

The solution is

y = e^{\frac{x}{2}} + 1

Popular Examples

log_{3}(x^2-x-5)=2

lo g_{3} (x^{2} - x - 5) = 2

solvefor x,ln((15)/x)=0 solve for

x, ln (\frac{15}{x}) = 0

1.023=ln((0.01667)/a)

1.023 = ln (\frac{0.01667}{a})

log_{4}(4x+2)-log_{4}(4-x)=1

lo g_{4} (4 x + 2) - lo g_{4} (4 - x) = 1

lo g_{6} (a) = 3

Frequently Asked Questions (FAQ)

What is the answer to solvefor y,x=2ln(y-1) ?
The answer to solvefor y,x=2ln(y-1) is y=e^{x/2}+1