What is the answer to 2.0028=-ln(0.02-x) ?

The answer to 2.0028=-ln(0.02-x) is x=-1/(e^{2.0028)}+0.02

Solve for x: 2.0028=-ln(0.02-x)

The solution is x=-1/(e^{2.0028)}+0.02

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2.0028 = - ln (0.02 - x)

x = - \frac{1}{e ^{2.0028}} + 0.02

Decimal Notation

x = - 0.11495 \dots

Solution steps

2.0028 = - ln (0.02 - x)

Move

ln (0.02 - x)

to the left side

2.0028 + ln (0.02 - x) = 0

Move

2.0028

to the right side

ln (0.02 - x) = - 2.0028

Apply log rules

0.02 - x = \frac{1}{e ^{2.0028}}

Solve

0.02 - x = \frac{1}{e ^{2.0028}} : x = - \frac{1}{e ^{2.0028}} + 0.02

x = - \frac{1}{e ^{2.0028}} + 0.02

Verify Solutions:

x = - \frac{1}{e ^{2.0028}} + 0.02

True

The solution is

x = - \frac{1}{e ^{2.0028}} + 0.02

lo g_{a} (x) = lo g_{2} (1)

lo g_{3}^{2} (x) - 2 lo g_{3} (x) = 0

x, lo g_{b} (x) = y

lo g_{3} (x) + lo g_{3} (a) = 0

ln (r) = 6

What is the answer to 2.0028=-ln(0.02-x) ?
The answer to 2.0028=-ln(0.02-x) is x=-1/(e^{2.0028)}+0.02
Solve for x: 2.0028=-ln(0.02-x)
The solution is x=-1/(e^{2.0028)}+0.02