What is the answer to log_{2}(x)-log_{4}(x)=2 ?

The answer to log_{2}(x)-log_{4}(x)=2 is x=16

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log_{2}(x)-log_{4}(x)=2

lo g_{2} (x) - lo g_{4} (x) = 2

x = 16

Solution steps

lo g_{2} (x) - lo g_{4} (x) = 2

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

ln (1 + e^{x}) = x

lo g_{4} (x + 5) - lo g_{4} (1 - 5 x) = 2

- ln (m^{2} - m + 1) = 0

p, ln (p) - ln (- p + 1) = t

3 lo g_{a^{3}} (x) = lo g_{a} (x)

What is the answer to log_{2}(x)-log_{4}(x)=2 ?
The answer to log_{2}(x)-log_{4}(x)=2 is x=16
Solve for x: log_{2}(x)-log_{4}(x)=2
The solution is x=16