What is the answer to 2log_{2}(x)-log_{2}(2x)=2 ?

The answer to 2log_{2}(x)-log_{2}(2x)=2 is x=8

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2log_{2}(x)-log_{2}(2x)=2

2 lo g_{2} (x) - lo g_{2} (2 x) = 2

x = 8

Solution steps

2 lo g_{2} (x) - lo g_{2} (2 x) = 2

Apply log rules

x = 8

Verify Solutions:

x = 8

True

The solution is

x = 8

lo g_{5} (10 x - 1) = lo g_{5} (9 x + 7)

0 = ln (x + 2)

x, ln (x) = 4 ln (t) + c

lo g_{3} (x) - 2 = lo g_{3} (x - 8)

x \frac{1}{2} ln (x - 1) = 0

What is the answer to 2log_{2}(x)-log_{2}(2x)=2 ?
The answer to 2log_{2}(x)-log_{2}(2x)=2 is x=8
Solve for x: 2log_{2}(x)-log_{2}(2x)=2
The solution is x=8