What is the answer to log_{2}(x)=0.96899 ?

The answer to log_{2}(x)=0.96899 is x=2^{0.96899}

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log_{2}(x)=0.96899

lo g_{2} (x) = 0.96899

x = 2^{0.96899}

Decimal Notation

x = 1.95746 \dots

Solution steps

lo g_{2} (x) = 0.96899

Apply log rules

x = 2^{0.96899}

ln (108) = - \frac{1}{4} ln (2 - 1 x)

lo g_{10} (2 - x) = 2

2 ln (\frac{3 + 1}{x}) = 0.001

ln (x) + ln (5 x) = - 3

ln (x) = \frac{2 - ln ( x )}{ln ( x )}

What is the answer to log_{2}(x)=0.96899 ?
The answer to log_{2}(x)=0.96899 is x=2^{0.96899}
Solve for x: log_{2}(x)=0.96899
The solution is x=2^{0.96899}