What is the answer to log_{36}(a)=log_{2}(x) ?

The answer to log_{36}(a)=log_{2}(x) is x=2^{log_{36}(a)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{36}(a)=log_{2}(x)

lo g_{36} (a) = lo g_{2} (x)

x = 2^{l o g_{36} (a)}

Solution steps

lo g_{36} (a) = lo g_{2} (x)

Apply log rules

2^{l o g_{36} (a)} = x

Switch sides

x = 2^{l o g_{36} (a)}

12 = \frac{lo g _{2} ( t )}{0.05}

x, ln (2 + x) = ln (y)

lo g_{5} (5 x + 5) - lo g_{5} (1 - x) = 1

2 ln (3 x^{2} + 1) - 13 = 0

lo g_{2} (x + 2) - lo g_{2} (x) = 1

What is the answer to log_{36}(a)=log_{2}(x) ?
The answer to log_{36}(a)=log_{2}(x) is x=2^{log_{36}(a)}