What is the answer to log_{5}(5x+5)-log_{5}(1-x)=1 ?

The answer to log_{5}(5x+5)-log_{5}(1-x)=1 is x=0

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log_{5}(5x+5)-log_{5}(1-x)=1

lo g_{5} (5 x + 5) - lo g_{5} (1 - x) = 1

x = 0

Solution steps

lo g_{5} (5 x + 5) - lo g_{5} (1 - x) = 1

Add

lo g_{5} (1 - x)

to both sides

lo g_{5} (5 x + 5) - lo g_{5} (1 - x) + lo g_{5} (1 - x) = 1 + lo g_{5} (1 - x)

Simplify

lo g_{5} (5 x + 5) = 1 + lo g_{5} (1 - x)

Apply log rules

5 x + 5 = 5 (1 - x)

Solve

5 x + 5 = 5 (1 - x) : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

2 ln (3 x^{2} + 1) - 13 = 0

lo g_{2} (x + 2) - lo g_{2} (x) = 1

lo g_{64} (r) = \frac{1}{3}

lo g_{7} (x + 5) + lo g_{7} (x - 1) = 1

lo g_{16} (N) = \frac{1}{4}

What is the answer to log_{5}(5x+5)-log_{5}(1-x)=1 ?
The answer to log_{5}(5x+5)-log_{5}(1-x)=1 is x=0
Solve for x: log_{5}(5x+5)-log_{5}(1-x)=1
The solution is x=0