What is the answer to (2-ln(x))ln(x)=0 ?

The answer to (2-ln(x))ln(x)=0 is x=e^2,x=1

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(2-ln(x))ln(x)=0

(2 - ln (x)) ln (x) = 0

x = e^{2}, x = 1

Decimal Notation

x = 7.38905 \dots, x = 1

Solution steps

(2 - ln (x)) ln (x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 - ln (x) = 0 or ln (x) = 0

Solve

2 - ln (x) = 0 : x = e^{2}

Solve

ln (x) = 0 : x = 1

Verify Solutions:

x = e^{2}

True

, x = 1

True

The solutions are

x = e^{2}, x = 1

4 + lo g_{2} (9 x) = 2

ln (x^{4}) - ln (x^{2}) - 2 = 0

lo g_{x - 3} (x^{2} - 3 x - 4) = 2

ln (x) + ln (5 - 2 x) = 0

lo g_{6561} (N) = - \frac{3}{4}

What is the answer to (2-ln(x))ln(x)=0 ?
The answer to (2-ln(x))ln(x)=0 is x=e^2,x=1
Solve for x: (2-ln(x))ln(x)=0
The solution is x=e^2,x=1