What is the answer to log_{2}(4x-9)=1 ?

The answer to log_{2}(4x-9)=1 is x= 11/4

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log_{2}(4x-9)=1

lo g_{2} (4 x - 9) = 1

x = \frac{11}{4}

Decimal Notation

x = 2.75

Solution steps

lo g_{2} (4 x - 9) = 1

Apply log rules

4 x - 9 = 2

Solve

4 x - 9 = 2 : x = \frac{11}{4}

x = \frac{11}{4}

lo g_{2} (x) - lo g_{4} (2 x - 1) = 1

x, ln (y) + y = x + ln (x) + c

lo g_{2} (3 x - 2) = 1 + lo g_{2} (5)

x, ln (x) = - 2.27

lo g_{e} (x) = 4.57

What is the answer to log_{2}(4x-9)=1 ?
The answer to log_{2}(4x-9)=1 is x= 11/4
Solve for x: log_{2}(4x-9)=1
The solution is x= 11/4