What is the answer to solvefor x,ln(y)+y=x+ln(x)+c ?

The answer to solvefor x,ln(y)+y=x+ln(x)+c is x=\W(y/(e^{c-y)})

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solvefor x,ln(y)+y=x+ln(x)+c

solve for

x, ln (y) + y = x + ln (x) + c

x = W (\frac{y}{e ^{c - y}})

Solution steps

ln (y) + y = x + ln (x) + c

Switch sides

x + ln (x) + c = ln (y) + y

Move

x

to the right side

ln (x) + c = ln (y) + y - x

Move

c

to the right side

ln (x) = ln (y) + y - x - c

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{l n (y) + y - x - c}

Simplify

e^{l n (x)} : x

Simplify

e^{l n (y) + y - x - c} : e^{y - x - c} y

x = e^{y - x - c} y

Solve

x = e^{y - x - c} y : x = W (\frac{y}{e ^{c - y}})

x = W (\frac{y}{e ^{c - y}})

lo g_{2} (3 x - 2) = 1 + lo g_{2} (5)

x, ln (x) = - 2.27

lo g_{e} (x) = 4.57

ln (x^{2} - 3 x) = 0

ln (x + 2) = ln (x) + ln (8) - ln (4)

What is the answer to solvefor x,ln(y)+y=x+ln(x)+c ?
The answer to solvefor x,ln(y)+y=x+ln(x)+c is x=\W(y/(e^{c-y)})