What is the answer to ln(x^2-3x)=0 ?

The answer to ln(x^2-3x)=0 is x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2

Solve for x: ln(x^2-3x)=0

The solution is x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2

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ln (x^{2} - 3 x) = 0

x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

Decimal Notation

x = 3.30277 \dots, x = - 0.30277 \dots

Solution steps

ln (x^{2} - 3 x) = 0

Apply log rules

x^{2} - 3 x = 1

Solve

x^{2} - 3 x = 1 : x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

ln (x + 2) = ln (x) + ln (8) - ln (4)

ln (10 - 0.9 v^{2}) = e^{- 27.642}

lo g_{4} (x) = 8, x

x + 5 ln (x - 1) = 3.46

3 = lo g_{2} (x^{2} + 2)

What is the answer to ln(x^2-3x)=0 ?
The answer to ln(x^2-3x)=0 is x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2
Solve for x: ln(x^2-3x)=0
The solution is x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2