What is the answer to 3=log_{2}(x^2+2) ?

The answer to 3=log_{2}(x^2+2) is x=sqrt(6),x=-sqrt(6)

Solve for x: 3=log_{2}(x^2+2)

The solution is x=sqrt(6),x=-sqrt(6)

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3 = lo g_{2} (x^{2} + 2)

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

3 = lo g_{2} (x^{2} + 2)

Apply log rules

8 = x^{2} + 2

Solve

8 = x^{2} + 2 : x = 6, x = - 6

x = 6, x = - 6

a, h = k + lo g_{10} (a c)

ln (x) = 19.21

9.6 = - lo g_{10} (x)

ln (x) = - 1.59

lo g_{10} (x + 2) = 2 - lo g_{10} (x)

What is the answer to 3=log_{2}(x^2+2) ?
The answer to 3=log_{2}(x^2+2) is x=sqrt(6),x=-sqrt(6)
Solve for x: 3=log_{2}(x^2+2)
The solution is x=sqrt(6),x=-sqrt(6)