What is the answer to log_{4}(3x^4)=4log_{4}(3x) ?

The answer to log_{4}(3x^4)=4log_{4}(3x) is No Solution for x\in\mathbb{R}

Solve for x: log_{4}(3x^4)=4log_{4}(3x)

The solution is No Solution for x\in\mathbb{R}

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lo g_{4} (3 x^{4}) = 4 lo g_{4} (3 x)

No Solution for x \in R

Solution steps

lo g_{4} (3 x^{4}) = 4 lo g_{4} (3 x)

Apply log rules

lo g_{4} (3) + 4 lo g_{4} (x) = 4 (lo g_{4} (3) + lo g_{4} (x))

Expand

4 (lo g_{4} (3) + lo g_{4} (x)) : 4 lo g_{4} (3) + 4 lo g_{4} (x)

lo g_{4} (3) + 4 lo g_{4} (x) = 4 lo g_{4} (3) + 4 lo g_{4} (x)

Move

lo g_{4} (3)

to the right side

4 lo g_{4} (x) = 4 lo g_{4} (x) + 3 lo g_{4} (3)

Move

4 lo g_{4} (x)

to the left side

0 = 3 lo g_{4} (3)

The sides are not equal

No Solution for x \in R

y, x = lo g_{e^{1}} (y)

16 ln (x) = lo g_{x} (e)

lo g_{5} (lo g_{2} (x)) = 1

y = ln (y) - 1

lo g_{5} (5 x - 1) = lo g_{5} (4 x + 5)

What is the answer to log_{4}(3x^4)=4log_{4}(3x) ?
The answer to log_{4}(3x^4)=4log_{4}(3x) is No Solution for x\in\mathbb{R}
Solve for x: log_{4}(3x^4)=4log_{4}(3x)
The solution is No Solution for x\in\mathbb{R}