What is the answer to 5log_{32}(A-7)=-1 ?

The answer to 5log_{32}(A-7)=-1 is A= 15/2

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5log_{32}(A-7)=-1

5 lo g_{32} (A - 7) = - 1

A = \frac{15}{2}

Decimal Notation

A = 7.5

Solution steps

5 lo g_{32} (A - 7) = - 1

Divide both sides by

5

lo g_{32} (A - 7) = - \frac{1}{5}

Apply log rules

A - 7 = \frac{1}{2}

Solve

A - 7 = \frac{1}{2} : A = \frac{15}{2}

A = \frac{15}{2}

Verify Solutions:

A = \frac{15}{2}

True

The solution is

A = \frac{15}{2}

lo g_{x} (100) = 3

2 = lo g_{b} (49)

lo g_{0.1} (x) = - 1

lo g_{7} (x) = 3.5

ln (4 x) = ln (12 + x)

What is the answer to 5log_{32}(A-7)=-1 ?
The answer to 5log_{32}(A-7)=-1 is A= 15/2
Solve for A: 5log_{32}(A-7)=-1
The solution is A= 15/2