What is the answer to 2=log_{b}(49) ?

The answer to 2=log_{b}(49) is b=7

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2=log_{b}(49)

2 = lo g_{b} (49)

b = 7

Solution steps

2 = lo g_{b} (49)

Apply log rules

2 = \frac{1}{lo g _{49} ( b )}

Multiply both sides by

lo g_{49} (b)

2 lo g_{49} (b) = \frac{1}{lo g _{49} ( b )} lo g_{49} (b)

Simplify

2 lo g_{49} (b) = 1

Divide both sides by

2

lo g_{49} (b) = \frac{1}{2}

Apply log rules

b = 7

Verify Solutions:

b = 7

True

The solution is

b = 7

lo g_{0.1} (x) = - 1

lo g_{7} (x) = 3.5

ln (4 x) = ln (12 + x)

x, f = ln (x + f)

ln (16 + x^{2}) = - ln (16 - x^{2})