What is the answer to ln(16+x^2)=-ln(16-x^2) ?

The answer to ln(16+x^2)=-ln(16-x^2) is x=sqrt(\sqrt{255)},x=-sqrt(\sqrt{255)}

Solve for x: ln(16+x^2)=-ln(16-x^2)

The solution is x=sqrt(\sqrt{255)},x=-sqrt(\sqrt{255)}

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ln (16 + x^{2}) = - ln (16 - x^{2})

x = 255, x = - 255

Decimal Notation

x = 3.99608 \dots, x = - 3.99608 \dots

Solution steps

ln (16 + x^{2}) = - ln (16 - x^{2})

Add

ln (16 - x^{2})

to both sides

ln (16 + x^{2}) + ln (16 - x^{2}) = - ln (16 - x^{2}) + ln (16 - x^{2})

Simplify

ln (16 + x^{2}) + ln (16 - x^{2}) = 0

Apply log rules

(16 + x^{2}) (16 - x^{2}) = 1

Solve

(16 + x^{2}) (16 - x^{2}) = 1 : x = 255, x = - 255

x = 255, x = - 255

Verify Solutions:

x = 255

True

, x = - 255

True

The solutions are

x = 255, x = - 255

32 = \frac{50}{ln ( q + 1 )}

ln (7 x) = 1

lo g_{10} (3 - 2 x) = 1

ln (x) - ln (5) = 0

ln (1) = ln (- 7 t)

What is the answer to ln(16+x^2)=-ln(16-x^2) ?
The answer to ln(16+x^2)=-ln(16-x^2) is x=sqrt(\sqrt{255)},x=-sqrt(\sqrt{255)}
Solve for x: ln(16+x^2)=-ln(16-x^2)
The solution is x=sqrt(\sqrt{255)},x=-sqrt(\sqrt{255)}