What is the answer to log_{4}(x-7)=log_{4}(x-4)+1 ?

The answer to log_{4}(x-7)=log_{4}(x-4)+1 is No Solution for x\in\mathbb{R}

Solve for x: log_{4}(x-7)=log_{4}(x-4)+1

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{4} (x - 7) = lo g_{4} (x - 4) + 1

No Solution for x \in R

Solution steps

lo g_{4} (x - 7) = lo g_{4} (x - 4) + 1

Apply log rules

x - 7 = (x - 4) \cdot 4

Solve

x - 7 = (x - 4) \cdot 4 : x = 3

x = 3

Verify Solutions:

x = 3

False

The solution is

No Solution for x \in R

ln (16 x - 15) - 15 ln (1) = 0

lo g_{e} (T + 273.15) = 877572

lo g_{2.71} (x) = 2.7

\frac{1}{2} = lo g_{16} (x)

x, lo g_{2} (2 x + 1) = 3

What is the answer to log_{4}(x-7)=log_{4}(x-4)+1 ?
The answer to log_{4}(x-7)=log_{4}(x-4)+1 is No Solution for x\in\mathbb{R}
Solve for x: log_{4}(x-7)=log_{4}(x-4)+1
The solution is No Solution for x\in\mathbb{R}